List every distinct Pipedrive people whose contact...

System: PD

people

System: CT

phone

System: CT

System: PD

person ID

SELECT DISTINCT COALESCE(pe.ct_id, pe.id) AS user_id, NULL AS email, NULL AS phone FROM pipedrive.persons_enriched AS pe WHERE 'email' = ANY(pe.pd_contact_preferences) AND NOT ('phone' = ANY(pe.pd_contact_preferences)) ORDER BY 1 ASC LIMIT 10000

SELECT DISTINCT
  COALESCE(pe.ct_id, pe.id) AS user_id,
  NULL AS email,
  NULL AS phone
FROM pipedrive.persons_enriched AS pe
WHERE
  'email' = ANY(
    pe.pd_contact_preferences
  )
  AND NOT (
    'phone' = ANY(
      pe.pd_contact_preferences
    )
  )
ORDER BY
  1 ASC
LIMIT 10000

List every distinct Pipedrive people whose contact preference array includes email but not phone. Return only user_id, in ascending order; use the person ID for a Pipedrive-only person.

Keeps only rows matching filters on pd_contact_preferences.

Summary: Reads rows from persons_enriched.


Independent synthetic fixture values, complete membership and required field types; not production or human usefulness.

Generation confidence; semantic correctness is only verified by the listed checks.

Generation confidence is not an answer certificate.

The entire question interpretation has not been independently verified.

System: PD

people

Declared intended trading frequency captured at onboarding (synced onward to Pipedrive).

Direct user_id; one row per user_id already. Project user_id first.

System: CT

trade frequency

System: CT

System: PD

person ID

Grain: The gold source's join key does not prove CT client identity; these sources cannot be safely combined. Project the CT account user_id or the Pipedrive person's verified ct_id as the join key. Deal, person and booking IDs are different identifiers.

SELECT c.user_id AS user_id FROM public.clients AS c WHERE NOT c.user_id IS NULL AND NOT c.trade_frequency IS NULL GROUP BY 1 HAVING COUNT(DISTINCT c.trade_frequency) > 1 ORDER BY 1 ASC

SELECT COALESCE(pe.ct_id, pe.id) AS user_id FROM pipedrive.persons_enriched AS pe WHERE CARDINALITY(pe.pd_trade_frequency) > 1 GROUP BY 1 ORDER BY 1 ASC LIMIT 10000

churn-tier-definitions declared-currency-intent activation-definition-gold client-type-sti-classes trade-existence-gold-booked

List every distinct Pipedrive people who declared more than one trade frequency. Return only user_id, in ascending order; use the person ID for a Pipedrive-only person.


First returned row — client_count: 32.00.

No complete question-to-answer semantic oracle was run.

SQL checks do not prove the whole question interpretation.

For exactly the Pipedrive people whose contact pre...

System: PD

people

Identity placeholder — NEVER select the physical column in SQL (the validator rejects it): project `NULL AS telephone`; the server fills real values post-execution keyed on user_id.

Project `id AS user_id` (accounts.id is the user key); one row per user already.

System: CT

phone

Onboarding/client dimension keyed by user_id (= accounts.id). Declared (not traded) currencies live here.

System: CT

client

Metric match

No predefined metrics are configured for this connection — scored on time clarity, query complexity and column visibility instead

Query complexity

Simple single-table query with basic aggregation

SELECT COUNT(DISTINCT pe.id) AS client_count, NULL AS email, NULL AS phone FROM pipedrive.persons_enriched AS pe WHERE 'email' = ANY(pe.pd_contact_preferences) AND NOT ('phone' = ANY(pe.pd_contact_preferences))

SELECT
  COUNT(DISTINCT pe.id) AS client_count,
  NULL AS email,
  NULL AS phone
FROM pipedrive.persons_enriched AS pe
WHERE
  'email' = ANY(
    pe.pd_contact_preferences
  )
  AND NOT (
    'phone' = ANY(
      pe.pd_contact_preferences
    )
  )

Show the underlying rows for this result.

For exactly the Pipedrive people whose contact preference array includes email but not phone in the first checked result, return their distinct count as client_count. Keep that membership and return zero if it is empty.

Calculates how many DISTINCT pe.id there are.

Summary: Works out how many DISTINCT pe.id there are from persons_enriched.


System: PD

people

System: CT

trade frequency

System: CT

client

Sql: The generated SQL could not complete the requested query. Name the group, measure, and date window in a new question.

SELECT COUNT(*) AS client_count FROM (SELECT public.clients.user_id FROM public.clients WHERE public.clients.trade_frequency IS NOT NULL AND public.clients.trade_frequency <> '' GROUP BY public.clients.user_id HAVING COUNT(DISTINCT public.clients.trade_frequency) > 1) AS multi_freq_users

SELECT c.user_id, COALESCE(NULLIF(c.client_name, ''), 'Client #' || c.user_id::text) AS client, COUNT(*) OVER () AS client_count FROM pipedrive.persons_enriched pe JOIN ct.client_360 c ON c.user_id = pe.ct_id WHERE pe.ct_id IS NOT NULL AND array_length(pe.pd_trade_frequency, 1) > 1 GROUP BY c.user_id, COALESCE(NULLIF(c.client_name, ''), 'Client #' || c.user_id::text)

For exactly the Pipedrive people who declared more than one trade frequency in the first checked result, return their distinct count as client_count. Keep that membership and return zero if it is empty.

CT data unavailable: The generated SQL could not complete the requested query.


27 rows returned. Only the first 12 returned rows are available for this summary.

Keyed merge and authoritative-source checks.

Keys, merge grain, and source membership were checked.

Show the same checked IDs for the Pipedrive people...

System: PD

people

System: CT

trade frequency

System: CT

0 matching rows — a filter likely did not bind; verify filters. High confidence (85%) — moderate complexity

Query times are separate. Source refresh time is unknown unless supplied.

SELECT c.user_id FROM ct.client_360 AS c JOIN pipedrive.persons_enriched AS pe ON pe.ct_id = c.user_id WHERE COALESCE(ARRAY_LENGTH(pe.pd_trade_frequency, 1), 0) > 1 GROUP BY c.user_id ORDER BY c.user_id DESC NULLS LAST LIMIT 10001

SELECT a.id AS user_id FROM public.accounts AS a JOIN public.clients AS c ON c.user_id = a.id WHERE NOT c.trade_frequency IS NULL AND c.trade_frequency <> '' GROUP BY a.id HAVING COUNT(DISTINCT c.trade_frequency) > 1 ORDER BY a.id DESC NULLS LAST LIMIT 10001

Measures retain their source and basis; they are not summed across sources.

Show the same checked IDs for the Pipedrive people who declared more than one trade frequency from the first result, this time in descending user_id order. Keep every member and show only user_id.

Gold / Pipedrive: Reads from client_360 and persons_enriched.

Gold / Pipedrive: Keeps only rows matching filters on pd_trade_frequency.

Gold / Pipedrive: Groups the results by user_id.

CT Ledger: Reads from accounts and clients.

CT Ledger: Keeps only rows matching filters on trade_frequency.

Summary: Combines the source results. Gold / Pipedrive: Reads rows from client_360 and persons_enriched grouped by user_id. CT Ledger: Reads rows from accounts and clients grouped by id.


System: PD

people

System: CT

trade frequency

System: CT

client

SELECT COUNT(DISTINCT c.user_id) AS client_count FROM public.clients c

SELECT pe.ct_id AS user_id FROM pipedrive.persons_enriched AS pe WHERE NOT pe.ct_id IS NULL AND CARDINALITY(pe.pd_trade_frequency) > 1 GROUP BY 1 ORDER BY 1 DESC NULLS LAST LIMIT 10000

Keep the Pipedrive people who declared more than one trade frequency membership from the third result and count those distinct IDs as client_count. An empty result counts as zero.


List every distinct Pipedrive people whose organiz...

System: PD

people

System: PD

organization

System: CT

System: PD

person ID

SELECT DISTINCT p.id AS user_id FROM pipedrive.persons AS p JOIN pipedrive.organizations AS o ON o.id = p.org_id WHERE COALESCE(ARRAY_LENGTH(o.cf_booking_hedging_policy, 1), 0) > 1 ORDER BY 1 LIMIT 10000

List every distinct Pipedrive people whose organization declares more than one booking or hedging policy. Return only user_id, in ascending order; use the person ID for a Pipedrive-only person.


32 rows returned. Only the first 12 returned rows are available for this summary.

System: PD

people

System: CT

phone

System: CT

SELECT pe.id AS user_id, NULL AS email, NULL AS phone FROM pipedrive.persons_enriched AS pe WHERE 'email' = ANY(pe.pd_contact_preferences) AND NOT ('phone' = ANY(pe.pd_contact_preferences)) ORDER BY pe.id DESC NULLS LAST LIMIT 10000

SELECT
  pe.id AS user_id,
  NULL AS email,
  NULL AS phone
FROM pipedrive.persons_enriched AS pe
WHERE
  'email' = ANY(
    pe.pd_contact_preferences
  )
  AND NOT (
    'phone' = ANY(
      pe.pd_contact_preferences
    )
  )
ORDER BY
  pe.id DESC NULLS LAST
LIMIT 10000

Show the same checked IDs for the Pipedrive people whose contact preference array includes email but not phone from the first result, this time in descending user_id order. Keep every member and show only user_id.

Summary: Reads rows from persons_enriched.


Keep the Pipedrive people whose contact preference...

System: PD

people

System: CT

phone

System: CT

client

Compare client count with the previous period.

Keep the Pipedrive people whose contact preference array includes email but not phone membership from the third result and count those distinct IDs as client_count. An empty result counts as zero.


24 rows returned. Only the first 12 returned rows are available for this summary.

List every distinct Pipedrive people at an organiz...

System: PD

people

System: PD

organization

System: PD

LinkedIn

System: PD

website

System: CT

System: PD

person ID

High confidence (85%) — moderate complexity

SELECT DISTINCT COALESCE(pe.ct_id, pe.id) AS user_id FROM pipedrive.persons_enriched AS pe JOIN pipedrive.organizations AS o ON o.id = pe.org_id WHERE NOT o.linkedin IS NULL AND o.linkedin <> '' AND (o.website IS NULL OR o.website = '') ORDER BY 1 LIMIT 10000

SELECT DISTINCT
  COALESCE(pe.ct_id, pe.id) AS user_id
FROM pipedrive.persons_enriched AS pe
JOIN pipedrive.organizations AS o
  ON o.id = pe.org_id
WHERE
  NOT o.linkedin IS NULL
  AND o.linkedin <> ''
  AND (
    o.website IS NULL OR o.website = ''
  )
ORDER BY
  1
LIMIT 10000

List every distinct Pipedrive people at an organization with a LinkedIn page and no website. Return only user_id, in ascending order; use the person ID for a Pipedrive-only person.

Reads from persons_enriched and organizations.

Keeps only rows matching filters on linkedin and website.

Summary: Reads rows from persons_enriched and organizations.


System: PD

people

System: PD

organization

System: CT

client

SELECT CAST(COUNT(DISTINCT public.accounts.id) AS DECIMAL) AS client_count FROM public.accounts WHERE public.accounts.deleted_at IS NULL

SELECT c.user_id, COUNT(DISTINCT c.user_id) OVER () AS client_count FROM pipedrive.persons_enriched pe JOIN ct.client_360 c ON c.user_id = pe.ct_id WHERE pe.pd_is_ct_employee IS NOT TRUE AND EXISTS (SELECT 1 FROM pipedrive.organizations o WHERE o.id = pe.org_id AND o.cf_booking_hedging_policy IS NOT NULL AND cardinality(o.cf_booking_hedging_policy) > 1) GROUP BY 1

For exactly the Pipedrive people whose organization declares more than one booking or hedging policy in the first checked result, return their distinct count as client_count. Keep that membership and return zero if it is empty.


System: PD

people

System: PD

organization

System: PD

LinkedIn

System: PD

website

System: CT

client

SELECT COUNT(DISTINCT a.id)::numeric AS client_count FROM public.accounts a

SELECT c.user_id, COUNT(DISTINCT pe.id)::int AS client_count FROM ct.client_360 c LEFT JOIN pipedrive.persons_enriched pe ON pe.ct_id = c.user_id LEFT JOIN pipedrive.organizations o ON o.id = pe.org_id AND o.linkedin IS NOT NULL AND o.website IS NULL GROUP BY 1

For exactly the Pipedrive people at an organization with a LinkedIn page and no website in the first checked result, return their distinct count as client_count. Keep that membership and return zero if it is empty.


System: PD

people

System: PD

organization

System: CT

SELECT pe.ct_id AS user_id FROM pipedrive.persons_enriched AS pe JOIN pipedrive.organizations AS o ON o.id = pe.org_id WHERE NOT pe.ct_id IS NULL AND CARDINALITY(COALESCE(o.cf_booking_hedging_policy, CAST(ARRAY[] AS TEXT[]))) > 1 ORDER BY pe.ct_id DESC NULLS LAST LIMIT 10000

Show the same checked IDs for the Pipedrive people whose organization declares more than one booking or hedging policy from the first result, this time in descending user_id order. Keep every member and show only user_id.

Keeps only rows matching filters on ct_id and cf_booking_hedging_policy.


Keep the Pipedrive people whose organization decla...

System: PD

people

System: PD

organization

System: CT

client

SELECT c.user_id, COUNT(DISTINCT pe.id)::bigint AS client_count FROM ct.client_360 c JOIN pipedrive.persons_enriched pe ON pe.ct_id = c.user_id JOIN pipedrive.organizations o ON o.id = pe.org_id WHERE cardinality(o.cf_booking_hedging_policy) > 1 GROUP BY 1 LIMIT 10001

SELECT tb.user_id, COUNT(*) FILTER (WHERE tb.status <> 'closed') AS trade_count, SUM(td.commission) FILTER (WHERE tb.status = 'settled') AS realized_revenue_gbp FROM public.trade_bookings tb LEFT JOIN public.trade_details td ON td.trade_booking_id = tb.id GROUP BY 1 LIMIT 10001

17 rows returned. Only the first 12 returned rows are available for this summary.

Returned row 3 — realized_revenue_gbp: £-14.30.

Keep the Pipedrive people whose organization declares more than one booking or hedging policy membership from the third result and count those distinct IDs as client_count. An empty result counts as zero.

Gold / Pipedrive: Reads from client_360, persons_enriched, and organizations.

Gold / Pipedrive: Calculates how many DISTINCT pe.id there are.

Gold / Pipedrive: Keeps only rows matching filters on cf_booking_hedging_policy.

CT Ledger: Reads from trade_bookings and trade_details.

CT Ledger: Calculates how many rows there are and the total of commission.

Summary: Combines the source results. Gold / Pipedrive: Works out how many DISTINCT pe.id there are from client_360, persons_enriched, and organizations grouped by user_id. CT Ledger: Works out how many rows there are and the total of commission from trade_bookings and trade_details grouped by user_id.


20 rows returned. Only the first 12 returned rows are available for this summary.

System: PD

people

System: PD

organization

System: PD

LinkedIn

System: PD

website

System: CT

SELECT pe.ct_id AS user_id FROM pipedrive.persons_enriched AS pe JOIN pipedrive.organizations AS o ON o.id = pe.org_id WHERE NOT o.linkedin IS NULL AND (o.website IS NULL OR o.website = '') AND NOT pe.ct_id IS NULL ORDER BY 1 DESC NULLS LAST LIMIT 10000

SELECT
  pe.ct_id AS user_id
FROM pipedrive.persons_enriched AS pe
JOIN pipedrive.organizations AS o
  ON o.id = pe.org_id
WHERE
  NOT o.linkedin IS NULL
  AND (
    o.website IS NULL OR o.website = ''
  )
  AND NOT pe.ct_id IS NULL
ORDER BY
  1 DESC NULLS LAST
LIMIT 10000

Show the same checked IDs for the Pipedrive people at an organization with a LinkedIn page and no website from the first result, this time in descending user_id order. Keep every member and show only user_id.

Keeps only rows matching filters on ct_id, linkedin, and website.


System: PD

people

System: PD

organization

System: PD

LinkedIn

System: PD

website

System: CT

client

SELECT COUNT(DISTINCT public.accounts.id) AS client_count FROM public.accounts

SELECT c.user_id, COUNT(DISTINCT pe.id) AS client_count FROM ct.client_360 c JOIN pipedrive.persons_enriched pe ON pe.ct_id = c.user_id JOIN pipedrive.organizations o ON o.id = pe.org_id WHERE o.linkedin IS NOT NULL AND o.website IS NULL GROUP BY 1

Keep the Pipedrive people at an organization with a LinkedIn page and no website membership from the third result and count those distinct IDs as client_count. An empty result counts as zero.


43 rows returned. Only the first 12 returned rows are available for this summary.

List every distinct Pipedrive people with an activ...

System: PD

people

System: PD

activity

System: PD

owner

System: CT

System: PD

person ID

SELECT DISTINCT COALESCE(p.ct_id, p.id) AS user_id FROM pipedrive.activities AS a JOIN pipedrive.deals AS d ON d.id = a.deal_id JOIN pipedrive.persons AS p ON p.id = a.person_id WHERE NOT a.assigned_to_user_id IS NULL AND NOT d.owner_id IS NULL AND a.assigned_to_user_id <> d.owner_id ORDER BY 1 LIMIT 10000

List every distinct Pipedrive people with an activity assigned to someone other than the owner of its deal. Return only user_id, in ascending order; use the person ID for a Pipedrive-only person.

Reads from activities, deals, and persons.

Keeps only rows matching filters on assigned_to_user_id and owner_id.

Summary: Reads rows from activities, deals, and persons.


38 rows returned. Only the first 12 returned rows are available for this summary.

System: PD

people

System: PD

owner

System: CT

System: PD

person ID

SELECT DISTINCT p.ct_id AS user_id FROM pipedrive.notes AS n JOIN pipedrive.deals AS d ON d.id = n.deal_id JOIN pipedrive.persons AS p ON p.id = d.person_id WHERE n.active_flag IS TRUE AND n.author_user_id IS DISTINCT FROM d.owner_id ORDER BY 1 LIMIT 10000

List every distinct Pipedrive people with an active deal note authored by someone other than the deal owner. Return only user_id, in ascending order; use the person ID for a Pipedrive-only person.

Keeps only rows matching filters on active_flag, author_user_id, and owner_id.

Summary: Reads rows from notes, deals, and persons.


First returned row — client_count: 43.00.

For exactly the Pipedrive people with an activity ...

System: PD

people

System: PD

activity

System: PD

owner

System: CT

client

SELECT COUNT(DISTINCT COALESCE(p.ct_id, p.id)) AS client_count FROM pipedrive.activities AS a JOIN pipedrive.deals AS d ON d.id = a.deal_id JOIN pipedrive.persons AS p ON p.id = a.person_id WHERE a.assigned_to_user_id IS NOT NULL AND d.owner_id IS NOT NULL AND a.assigned_to_user_id <> d.owner_id

SELECT
  COUNT(DISTINCT COALESCE(p.ct_id, p.id)) AS client_count
FROM pipedrive.activities AS a
JOIN pipedrive.deals AS d
  ON d.id = a.deal_id
JOIN pipedrive.persons AS p
  ON p.id = a.person_id
WHERE
  NOT a.assigned_to_user_id IS NULL
  AND NOT d.owner_id IS NULL
  AND a.assigned_to_user_id <> d.owner_id

For exactly the Pipedrive people with an activity assigned to someone other than the owner of its deal in the first checked result, return their distinct count as client_count. Keep that membership and return zero if it is empty.

Calculates how many DISTINCT COALESCE(p.ct_id, p.id) there are.

Summary: Works out how many DISTINCT COALESCE(p.ct_id, p.id) there are from activities, deals, and persons.


For exactly the Pipedrive people with an active de...

System: PD

people

System: PD

owner

System: CT

client

SELECT COUNT(DISTINCT p.ct_id)::bigint AS client_count FROM pipedrive.notes AS n JOIN pipedrive.deals AS d ON d.id = n.deal_id JOIN pipedrive.persons AS p ON p.id = d.person_id WHERE n.active_flag IS TRUE AND n.author_user_id IS DISTINCT FROM d.owner_id

SELECT
  CAST(COUNT(DISTINCT p.ct_id) AS BIGINT) AS client_count
FROM pipedrive.notes AS n
JOIN pipedrive.deals AS d
  ON d.id = n.deal_id
JOIN pipedrive.persons AS p
  ON p.id = d.person_id
WHERE
  n.active_flag IS TRUE AND n.author_user_id IS DISTINCT FROM d.owner_id

For exactly the Pipedrive people with an active deal note authored by someone other than the deal owner in the first checked result, return their distinct count as client_count. Keep that membership and return zero if it is empty.

Calculates how many DISTINCT p.ct_id there are.

Summary: Works out how many DISTINCT p.ct_id there are from notes, deals, and persons.


System: PD

people

System: PD

activity

System: PD

owner

System: CT

SELECT DISTINCT pe.id AS user_id FROM pipedrive.activities AS a JOIN pipedrive.deals AS d ON d.id = a.deal_id JOIN pipedrive.persons_enriched AS pe ON pe.id = a.person_id WHERE a.assigned_to_user_id IS DISTINCT FROM d.owner_id ORDER BY 1 DESC NULLS LAST LIMIT 10000

Show the same checked IDs for the Pipedrive people with an activity assigned to someone other than the owner of its deal from the first result, this time in descending user_id order. Keep every member and show only user_id.

Reads from activities, deals, and persons_enriched.

Summary: Reads rows from activities, deals, and persons_enriched.


Keep the Pipedrive people with an activity assigne...

System: PD

people

System: PD

activity

System: PD

owner

System: CT

client

SELECT COUNT(DISTINCT pe.id) AS client_count FROM pipedrive.activities AS a JOIN pipedrive.deals AS d ON d.id = a.deal_id JOIN pipedrive.persons_enriched AS pe ON pe.id = a.person_id WHERE a.assigned_to_user_id IS DISTINCT FROM d.owner_id

Keep the Pipedrive people with an activity assigned to someone other than the owner of its deal membership from the third result and count those distinct IDs as client_count. An empty result counts as zero.

Calculates how many DISTINCT pe.id there are.

Summary: Works out how many DISTINCT pe.id there are from activities, deals, and persons_enriched.


70 rows returned. Only the first 12 returned rows are available for this summary.

List every distinct Pipedrive people explicitly ma...

System: PD

people

Client sign-up / registration timestamp.

System: CT

signup date

System: CT

System: PD

person ID

SELECT a.id AS user_id FROM public.accounts AS a ORDER BY a.id ASC LIMIT 10000

activation-definition activation-definition-gold onboarding-duration churn-tier-definitions declared-currency-intent client-type-sti-classes trade-existence-gold-booked

List every distinct Pipedrive people explicitly marked as non-employees whose lead qualification date follows their signup date. Return only user_id, in ascending order; use the person ID for a Pipedrive-only person.

Summary: Reads rows from accounts.


System: PD

people

System: PD

owner

System: CT

SELECT DISTINCT p.ct_id AS user_id FROM pipedrive.notes AS n JOIN pipedrive.persons AS p ON p.id = n.person_id JOIN pipedrive.deals AS d ON d.id = n.deal_id WHERE n.active_flag = TRUE AND NOT n.deal_id IS NULL AND n.author_user_id IS DISTINCT FROM d.owner_id ORDER BY 1 DESC NULLS LAST LIMIT 10000

Show the same checked IDs for the Pipedrive people with an active deal note authored by someone other than the deal owner from the first result, this time in descending user_id order. Keep every member and show only user_id.

Keeps only rows matching filters on author_user_id, owner_id, active_flag, and deal_id.

Summary: Reads rows from notes, persons, and deals.


System: PD

people

System: CT

signup date

System: CT

client

Semantic: Unverified calendar semantics: physical timestamp type or lineage is missing Use the requested calendar and the authorized physical timestamp type. Convert naive UTC storage to an instant before converting to the requested wall clock; convert timestamptz directly to that wall clock. Compare compatible timestamp types.

WITH pipedrive_non_employees AS (SELECT a.id AS user_id FROM public.accounts AS a WHERE NOT CAST(NULL AS BOOLEAN) IS NULL OR (CAST(NULL AS TIMESTAMP) > ((a.created_at) AT TIME ZONE 'UTC') AT TIME ZONE 'Europe/London')) SELECT COUNT(DISTINCT user_id) AS client_count FROM pipedrive_non_employees

WITH pipedrive_non_employees AS (
  SELECT
    a.id AS user_id
  FROM public.accounts AS a
  WHERE
    NOT CAST(NULL AS BOOLEAN) IS NULL
    OR (
      CAST(NULL AS TIMESTAMP) > (
        (
          a.created_at
        ) AT TIME ZONE 'UTC'
      ) AT TIME ZONE 'Europe/London'
    )
)
SELECT
  COUNT(DISTINCT user_id) AS client_count
FROM pipedrive_non_employees

activation-definition activation-definition-gold onboarding-duration declared-currency-intent client-type-sti-classes

For exactly the Pipedrive people explicitly marked as non-employees whose lead qualification date follows their signup date in the first checked result, return their distinct count as client_count. Keep that membership and return zero if it is empty.


Keep the Pipedrive people with an active deal note...

System: PD

people

System: PD

owner

System: CT

client

SELECT COUNT(DISTINCT p.ct_id) AS client_count FROM pipedrive.notes AS n JOIN pipedrive.persons AS p ON p.id = n.person_id JOIN pipedrive.deals AS d ON d.id = n.deal_id WHERE n.active_flag = TRUE AND NOT n.deal_id IS NULL AND n.author_user_id IS DISTINCT FROM d.owner_id

Keep the Pipedrive people with an active deal note authored by someone other than the deal owner membership from the third result and count those distinct IDs as client_count. An empty result counts as zero.

Summary: Works out how many DISTINCT p.ct_id there are from notes, persons, and deals.


System: PD

people

System: CT

signup date

System: CT

SELECT a.id AS user_id FROM public.accounts AS a ORDER BY a.id DESC NULLS LAST LIMIT 10000

Show the same checked IDs for the Pipedrive people explicitly marked as non-employees whose lead qualification date follows their signup date from the first result, this time in descending user_id order. Keep every member and show only user_id.

Summary: Reads rows from accounts.


System: PD

people

System: PD

organization

System: CT

System: PD

person ID

Schema: The query refers to a table or column that is unavailable on the selected connection. Rephrase to only request data you have access to

The query tried to access restricted data or operations

Contact support if you believe this is an error

SELECT DISTINCT COALESCE(pe.ct_id, pe.id) AS user_id FROM pipedrive.persons_enriched pe JOIN pipedrive.organizations o ON o.id = pe.org_id WHERE (SELECT COUNT(DISTINCT e) FROM unnest(o.cf_erp) AS e) >= 2 ORDER BY 1

SELECT DISTINCT
  COALESCE(pe.ct_id, pe.id) AS user_id
FROM pipedrive.persons_enriched AS pe
JOIN pipedrive.organizations AS o
  ON o.id = pe.org_id
WHERE
  (
    SELECT
      COUNT(DISTINCT e)
    FROM UNNEST(o.cf_erp) AS e
  ) >= 2
ORDER BY
  1

List every distinct Pipedrive people whose organization names at least two ERP systems. Return only user_id, in ascending order; use the person ID for a Pipedrive-only person.

The generated query couldn't be validated. This might be due to security restrictions or invalid SQL.


System: PD

people

System: CT

signup date

System: CT

client

Semantic: The query could not preserve the requested meaning or scope. Name the group, measure, and date window in a new question.

Keep the Pipedrive people explicitly marked as non-employees whose lead qualification date follows their signup date membership from the third result and count those distinct IDs as client_count. An empty result counts as zero.


System: PD

people

System: PD

organization

System: CT

client

For exactly the Pipedrive people whose organization names at least two ERP systems in the first checked result, return their distinct count as client_count. Keep that membership and return zero if it is empty.


System: PD

people

System: PD

organization

System: PD

wallet-share

System: CT

System: CT

System: PD

System: both

System: PD

value

System: CT

System: PD

person ID

Medium confidence (69%) — implicit time period, moderate complexity

SELECT DISTINCT COALESCE(pe.ct_id, pe.id) AS user_id FROM pipedrive.persons_enriched AS pe JOIN pipedrive.organizations AS o ON o.id = pe.org_id WHERE NOT o.cf_level_of_service IS NULL AND o.cf_wallet_share IS NULL ORDER BY 1 LIMIT 10000

List every distinct Pipedrive people at an organization with a known service level but an unknown wallet-share value. Return only user_id, in ascending order; use the person ID for a Pipedrive-only person.

Reads from persons_enriched and organizations.

Keeps only rows matching filters on cf_wallet_share and cf_level_of_service.


System: PD

people

System: PD

organization

System: CT

SELECT pe.ct_id AS user_id FROM pipedrive.persons_enriched AS pe JOIN pipedrive.organizations AS o ON o.id = pe.org_id WHERE NOT o.cf_erp IS NULL AND ARRAY_LENGTH(o.cf_erp, 1) >= 2 AND NOT pe.ct_id IS NULL ORDER BY 1 DESC NULLS LAST LIMIT 10000

Show the same checked IDs for the Pipedrive people whose organization names at least two ERP systems from the first result, this time in descending user_id order. Keep every member and show only user_id.

Keeps only rows matching filters on ct_id and cf_erp.


System: PD

people

System: PD

organization

System: CT

client

```json
{
  "sql": "",
  "explanation": "This request depends on Pipedrive/CRM organization data ('ERP systems membership from the third result') that does not exist on this CT-production connection, so no CT-side SQL can answer it.",
  "confidence": "uncertain",
  "warnings": [
    "No Pipedrive pe

Keep the Pipedrive people whose organization names at least two ERP systems membership from the third result and count those distinct IDs as client_count. An empty result counts as zero.


First returned row — client_count: 1.00.

For exactly the Pipedrive people at an organizatio...

System: PD

people

System: PD

organization

System: PD

wallet-share

System: CT

System: CT

System: PD

System: both

System: PD

value

System: CT

client

SELECT c360.user_id AS user_id, COUNT(DISTINCT pe.id) AS client_count FROM ct.client_360 c360 JOIN pipedrive.persons_enriched pe ON pe.ct_id = c360.user_id JOIN pipedrive.organizations o ON o.id = pe.org_id WHERE o.cf_level_of_service IS NOT NULL AND o.cf_wallet_share IS NULL GROUP BY 1 LIMIT 10001

SELECT a.id AS user_id, CAST(1 AS DECIMAL) AS client_flag FROM public.accounts AS a LIMIT 10001

13 rows returned. Only the first 12 returned rows are available for this summary.

For exactly the Pipedrive people at an organization with a known service level but an unknown wallet-share value in the first checked result, return their distinct count as client_count. Keep that membership and return zero if it is empty.

Gold / Pipedrive: Reads from client_360, persons_enriched, and organizations.

Gold / Pipedrive: Calculates how many DISTINCT pe.id there are.

Gold / Pipedrive: Keeps only rows matching filters on cf_wallet_share and cf_level_of_service.

Gold / Pipedrive: Groups the results by user_id.

Summary: Combines the source results. Gold / Pipedrive: Works out how many DISTINCT pe.id there are from client_360, persons_enriched, and organizations grouped by user_id. CT Ledger: Reads rows from accounts.


22 rows returned. Only the first 12 returned rows are available for this summary.

System: PD

people

System: PD

activity

System: PD

duration

System: PD

due time

System: CT

System: PD

person ID

High confidence (100%) — clear time period, simple query

SELECT DISTINCT a.person_id AS user_id FROM pipedrive.activities AS a WHERE NOT a.duration IS NULL AND (a.due_time IS NULL OR a.due_time = '') ORDER BY 1 LIMIT 10000

SELECT DISTINCT
  a.person_id AS user_id
FROM pipedrive.activities AS a
WHERE
  NOT a.duration IS NULL AND (
    a.due_time IS NULL OR a.due_time = ''
  )
ORDER BY
  1
LIMIT 10000

List every distinct Pipedrive people with an activity that has a duration but no due time. Return only user_id, in ascending order; use the person ID for a Pipedrive-only person.

Keeps only rows matching filters on duration and due_time.

Summary: Reads rows from activities.


System: PD

people

System: PD

organization

System: PD

wallet-share

System: CT

System: CT

System: PD

System: both

System: PD

value

System: CT

SELECT pe.ct_id AS user_id FROM pipedrive.persons_enriched AS pe JOIN pipedrive.organizations AS o ON o.id = pe.org_id WHERE NOT o.cf_level_of_service IS NULL AND o.cf_wallet_share IS NULL AND NOT pe.ct_id IS NULL ORDER BY pe.ct_id DESC NULLS LAST LIMIT 10000

Show the same checked IDs for the Pipedrive people at an organization with a known service level but an unknown wallet-share value from the first result, this time in descending user_id order. Keep every member and show only user_id.

Keeps only rows matching filters on cf_wallet_share, ct_id, and cf_level_of_service.


First returned row — client_count: 22.00.

System: PD

people

System: PD

activity

System: PD

duration

System: PD

due time

System: CT

client

SELECT COUNT(DISTINCT a.person_id) AS client_count FROM pipedrive.activities AS a WHERE a.person_id IS NOT NULL AND a.duration IS NOT NULL AND (a.due_time IS NULL OR a.due_time = '')

SELECT
  COUNT(DISTINCT a.person_id) AS client_count
FROM pipedrive.activities AS a
WHERE
  NOT a.person_id IS NULL
  AND NOT a.duration IS NULL
  AND (
    a.due_time IS NULL OR a.due_time = ''
  )

For exactly the Pipedrive people with an activity that has a duration but no due time in the first checked result, return their distinct count as client_count. Keep that membership and return zero if it is empty.

Calculates how many DISTINCT a.person_id there are.

Keeps only rows matching filters on person_id, duration, and due_time.

Summary: Works out how many DISTINCT a.person_id there are from activities.


System: PD

people

System: PD

activity

System: PD

duration

System: PD

due time

System: CT

SELECT DISTINCT a.user_id FROM pipedrive.activities AS a WHERE NOT a.duration IS NULL AND a.due_time IS NULL ORDER BY 1 DESC NULLS LAST LIMIT 10000

Missing values occur in 1 of the 1 rows examined.

Show the same checked IDs for the Pipedrive people with an activity that has a duration but no due time from the first result, this time in descending user_id order. Keep every member and show only user_id.

Keeps only rows matching filters on due_time and duration.

Summary: Reads rows from activities.


First returned row — client_count: 0.00.

Keep the Pipedrive people with an activity that ha...

System: PD

people

System: PD

activity

System: PD

duration

System: PD

due time

System: CT

client

SELECT COUNT(DISTINCT a.user_id) AS client_count FROM pipedrive.activities AS a WHERE NOT a.duration IS NULL AND a.due_time IS NULL

Keep the Pipedrive people with an activity that has a duration but no due time membership from the third result and count those distinct IDs as client_count. An empty result counts as zero.

Calculates how many DISTINCT a.user_id there are.

Summary: Works out how many DISTINCT a.user_id there are from activities.


System: PD

people

System: PD

organization

System: PD

wallet-share

System: CT

System: CT

System: PD

System: both

System: PD

value

System: CT

client

SELECT COUNT(DISTINCT a.id) AS client_count FROM public.accounts a

SELECT c360.user_id, COUNT(DISTINCT c360.user_id) OVER () AS client_count, o.cf_level_of_service FROM ct.client_360 c360 JOIN pipedrive.persons_enriched pe ON pe.ct_id = c360.user_id JOIN pipedrive.organizations o ON o.id = pe.org_id WHERE o.cf_level_of_service IS NOT NULL AND o.cf_wallet_share IS NULL GROUP BY 1, 3, c360.user_id

Keep the Pipedrive people at an organization with a known service level but an unknown wallet-share value membership from the third result and count those distinct IDs as client_count. An empty result counts as zero.


System: PD

people

System: PD

organization

System: CT

client-type

System: CT

System: PD

person ID

SELECT DISTINCT COALESCE(pe.ct_id, pe.id) AS user_id FROM pipedrive.persons_enriched AS pe JOIN pipedrive.organizations AS o ON o.id = pe.org_id WHERE COALESCE(ARRAY_LENGTH(o.cf_client_type_tags, 1), 0) > 1 ORDER BY 1 LIMIT 10000

List every distinct Pipedrive people at an organization with more than one client-type tag. Return only user_id, in ascending order; use the person ID for a Pipedrive-only person.

Keeps only rows matching filters on cf_client_type_tags.


44 rows returned. Only the first 12 returned rows are available for this summary.

List every distinct Pipedrive people with a deal w...

System: PD

people

System: PD

stage

System: CT

System: PD

person ID

High confidence (85%) — clear time period, moderate complexity

SELECT DISTINCT COALESCE(p.ct_id, p.id) AS user_id FROM pipedrive.deals AS d JOIN pipedrive.persons AS p ON p.id = d.person_id WHERE d.stage_change_time < d.add_time ORDER BY 1 LIMIT 10000

List every distinct Pipedrive people with a deal whose stage-change timestamp predates its creation timestamp. Return only user_id, in ascending order; use the person ID for a Pipedrive-only person.

Keeps only rows matching filters on stage_change_time and add_time.

Summary: Reads rows from deals and persons.


For exactly the Pipedrive people with a deal whose...

System: PD

people

System: PD

stage

System: CT

client

SELECT COUNT(DISTINCT COALESCE(p.ct_id, p.id)) AS client_count FROM pipedrive.deals AS d JOIN pipedrive.persons AS p ON p.id = d.person_id WHERE d.stage_change_time < d.add_time

For exactly the Pipedrive people with a deal whose stage-change timestamp predates its creation timestamp in the first checked result, return their distinct count as client_count. Keep that membership and return zero if it is empty.

Calculates how many DISTINCT COALESCE(p.ct_id, p.id) there are.

Summary: Works out how many DISTINCT COALESCE(p.ct_id, p.id) there are from deals and persons.


First returned row — client_count (pipeline): 1.00.

System: PD

people

System: PD

organization

System: CT

client-type

System: CT

client

Moderate complexity: 1 JOINs, subqueries

SELECT c360.user_id, COUNT(DISTINCT pe.id) AS client_count FROM ct.client_360 c360 JOIN pipedrive.persons_enriched pe ON pe.ct_id = c360.user_id WHERE EXISTS (SELECT 1 FROM pipedrive.organizations o WHERE o.id = pe.org_id AND o.cf_client_type_tags IS NOT NULL AND array_length(o.cf_client_type_tags, 1) > 1) GROUP BY 1 LIMIT 10001

SELECT a.id AS user_id, COUNT(DISTINCT c.type) AS client_count FROM public.accounts a LEFT JOIN public.clients c ON c.user_id = a.id GROUP BY 1 LIMIT 10001

Break client count (pipeline) down by month.

Compare client count (pipeline) with the previous period.

First returned row — client_count (realized): 1.00.

For exactly the Pipedrive people at an organization with more than one client-type tag in the first checked result, return their distinct count as client_count. Keep that membership and return zero if it is empty.

Gold / Pipedrive: Keeps only rows matching filters on id, org_id, and cf_client_type_tags.

CT Ledger: Reads from accounts and clients.

CT Ledger: Calculates how many DISTINCT c.type there are.

Summary: Combines the source results. Gold / Pipedrive: Works out how many DISTINCT pe.id there are from client_360, persons_enriched, and organizations grouped by user_id. CT Ledger: Works out how many DISTINCT c.type there are from accounts and clients grouped by id.


System: PD

people

System: PD

stage

System: CT

SELECT DISTINCT p.ct_id AS user_id FROM pipedrive.persons AS p JOIN pipedrive.deals AS d ON d.person_id = p.id WHERE NOT d.stage_change_time IS NULL AND NOT d.add_time IS NULL AND d.stage_change_time < d.add_time AND NOT p.ct_id IS NULL ORDER BY 1 DESC NULLS LAST LIMIT 10000

Show the same checked IDs for the Pipedrive people with a deal whose stage-change timestamp predates its creation timestamp from the first result, this time in descending user_id order. Keep every member and show only user_id.

Keeps only rows matching filters on stage_change_time, add_time, and ct_id.

Summary: Reads rows from persons and deals.


System: PD

people

System: PD

organization

System: CT

client-type

System: CT

SELECT pe.ct_id AS user_id FROM pipedrive.persons_enriched AS pe JOIN pipedrive.organizations AS o ON o.id = pe.org_id WHERE COALESCE(ARRAY_LENGTH(o.cf_client_type_tags, 1), 0) > 1 ORDER BY 1 DESC NULLS LAST LIMIT 10000

Show the same checked IDs for the Pipedrive people at an organization with more than one client-type tag from the first result, this time in descending user_id order. Keep every member and show only user_id.

Reads from persons_enriched and organizations.


System: PD

people

System: PD

organization

System: CT

client-type

System: CT

client

```json
{
  "sql": "",
  "explanation": "The requested filter (Pipedrive people with more than one client-type tag membership, from a prior result) and the client_count measure are entirely Pipedrive/GOLD-leg concepts; this CT-production connection has no tables that can compute them.",
  "confidenc

Keep the Pipedrive people at an organization with more than one client-type tag membership from the third result and count those distinct IDs as client_count. An empty result counts as zero.


Keep the Pipedrive people with a deal whose stage-...

System: PD

people

System: PD

stage

System: CT

client

SELECT COUNT(DISTINCT p.ct_id) AS client_count FROM pipedrive.persons AS p JOIN pipedrive.deals AS d ON d.person_id = p.id WHERE NOT d.stage_change_time IS NULL AND NOT d.add_time IS NULL AND d.stage_change_time < d.add_time AND NOT p.ct_id IS NULL

Keep the Pipedrive people with a deal whose stage-change timestamp predates its creation timestamp membership from the third result and count those distinct IDs as client_count. An empty result counts as zero.

Calculates how many DISTINCT p.ct_id there are.

Summary: Works out how many DISTINCT p.ct_id there are from persons and deals.